重新编写函数squeeze(s1,s2)，将字符串s1中任何与字符串s2中的字符匹配的字符都删除。(把匹配的字符替换为’\0’)
代码：
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| #include <stdio.h>
void squeeze(char* s1,char* s2)
{
int i = 0;
int j = 0;
for (i=0; s1[i]!='\0'; i++)
{
for (j=0; s2[j]!='\0'; j++)
{
if (s1[i] == s2[j])
{
s1[i] = 0;
break;
}
}
}
}
int main() {
char s1[10] = "abcdefghi";
char s2[3] = "bd";
squeeze(s1,s2);
return 0;
}
|